2022浙江省赛初赛
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WriteUp
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JBNRZ

614 字
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7 分钟
本文最后更新于 514 天前，其中的信息可能已经有所发展或是发生改变。

可恶，太菜了

Web

nisc_easyweb

题解

  • dirsearch扫描得到robots.txt
  • 访问/api/record/，得到api_test.php
  • 访问查看源代码，找到hint
  • get参数得到flag

吃豆人吃豆魂

题解

  • 查看源代码，在index.js发现base64的flag

Misc

chechin_gift

题解

  • 010查看附件，结尾存在base64
  • 替换码表
    • N-ZA-Mn-za-m0-9+/=
    • base32
    • DASCTF{722433fc22f2e79959da2208d84cbb40}

m4a

题解

  • 打开音频文件，很明显是一串摩尔斯密码，转换为 MP3，拖入 Audacity 查看波形图
    • 1000 01 00001 00011 1000 1010 0 0010 1010 00111 11111 00001
    • BA43BCEFC204
  • 010查看m4a
  • 文件结尾有倒置的 PK 文件，写脚本
with open('1.m4a', 'rb') as rb:
    content = rb.read().hex()
a = content[::-2]
b = ' ' + content[::-1]
b = b[::2].replace(' ', '')
c = ''
for i in range(len(a)):
    c += b[i]
    c += a[i]
with open('1.txt', 'w') as w:
    w.write(c)
  • 导入010，运行zip模板删除多余内容，用key解压
  • 看 wp 知道这是 rot47+atbash
    • DASCTF{5e0f98a95f79829b7a484a54066cb08f}

Unkn0wnData

题解

  • 010打开，结尾存在base64，magic爆破加密
  • 图片存在LSB隐写，保存 bin
  • 解压zip得到

data:
0000100000000000
00000c0000000000
00000e0000000000
00002a0000000000
0000100000000000
0000040000000000
0000080000000000
00002a0000000000
0000160000000000
00000b0000000000
00000c0000000000
00001c0000000000
00002a0000000000
00002c0000000000
0200340000000000
00002a0000000000
0200090000000000
00000c0000000000
0000110000000000
0000070000000000
0200170000000000
00002a0000000000
0200170000000000
00000b0000000000
0000080000000000
0000120000000000
00002a0000000000
0200150000000000
0000080000000000
0000040000000000
00000f0000000000
00000a0000000000
00002a0000000000
02000e0000000000
0000080000000000
00001c0000000000
00000a0000000000
00002a0000000000
0000040000000000
0000110000000000
0000070000000000
00000f0000000000
00002a0000000000
0200100000000000
0000040000000000
00000e0000000000
0000080000000000
0000080000000000
00002a0000000000
02000c0000000000
0000170000000000
02001e0000000000
0000070000000000
00002a0000000000

  • 键盘流量
    • mikmaeshiy:FindTTheoRealgKeygandlMakeeIt!d
    • mimashi FindTheRealKeyandMakeIt!
normalKeys = {"04":"a", "05":"b", "06":"c", "07":"d", "08":"e", "09":"f", "0a":"g", "0b":"h", "0c":"i", "0d":"j", "0e":"k", "0f":"l", "10":"m", "11":"n", "12":"o", "13":"p", "14":"q", "15":"r", "16":"s", "17":"t", "18":"u", "19":"v", "1a":"w", "1b":"x", "1c":"y", "1d":"z","1e":"1", "1f":"2", "20":"3", "21":"4", "22":"5", "23":"6","24":"7","25":"8","26":"9","27":"0","28":"<RET>","29":"<ESC>","2a":"<DEL>", "2b":"\t","2c":"<SPACE>","2d":"-","2e":"=","2f":"[","30":"]","31":"\\","32":"<NON>","33":";","34":"'","35":"<GA>","36":",","37":".","38":"/","39":"<CAP>","3a":"<F1>","3b":"<F2>", "3c":"<F3>","3d":"<F4>","3e":"<F5>","3f":"<F6>","40":"<F7>","41":"<F8>","42":"<F9>","43":"<F10>","44":"<F11>","45":"<F12>"}

shiftKeys = {"04":"A", "05":"B", "06":"C", "07":"D", "08":"E", "09":"F", "0a":"G", "0b":"H", "0c":"I", "0d":"J", "0e":"K", "0f":"L", "10":"M", "11":"N", "12":"O", "13":"P", "14":"Q", "15":"R", "16":"S", "17":"T", "18":"U", "19":"V", "1a":"W", "1b":"X", "1c":"Y", "1d":"Z","1e":"!", "1f":"@", "20":"#", "21":"$", "22":"%", "23":"^","24":"&","25":"*","26":"(","27":")","28":"<RET>","29":"<ESC>","2a":"<DEL>", "2b":"\t","2c":"<SPACE>","2d":"_","2e":"+","2f":"{","30":"}","31":"|","32":"<NON>","33":"\"","34":":","35":"<GA>","36":"<","37":">","38":"?","39":"<CAP>","3a":"<F1>","3b":"<F2>", "3c":"<F3>","3d":"<F4>","3e":"<F5>","3f":"<F6>","40":"<F7>","41":"<F8>","42":"<F9>","43":"<F10>","44":"<F11>","45":"<F12>"}

keys = open('key.txt')
output = ""
for line in keys:
    k = line[1]
    n = line[4:6]
    if k == '0':
        print(normalKeys[n], end='')
    elif k == '2':
        print(shiftKeys[n], end='')
normalKeys = {"04":"a", "05":"b", "06":"c", "07":"d", "08":"e", "09":"f", "0a":"g", "0b":"h", "0c":"i", "0d":"j", "0e":"k", "0f":"l", "10":"m", "11":"n", "12":"o", "13":"p", "14":"q", "15":"r", "16":"s", "17":"t", "18":"u", "19":"v", "1a":"w", "1b":"x", "1c":"y", "1d":"z","1e":"1", "1f":"2", "20":"3", "21":"4", "22":"5", "23":"6","24":"7","25":"8","26":"9","27":"0","28":"<RET>","29":"<ESC>","2a":"<DEL>", "2b":"\t","2c":"<SPACE>","2d":"-","2e":"=","2f":"[","30":"]","31":"\\","32":"<NON>","33":";","34":"'","35":"<GA>","36":",","37":".","38":"/","39":"<CAP>","3a":"<F1>","3b":"<F2>", "3c":"<F3>","3d":"<F4>","3e":"<F5>","3f":"<F6>","40":"<F7>","41":"<F8>","42":"<F9>","43":"<F10>","44":"<F11>","45":"<F12>"}

shiftKeys = {"04":"A", "05":"B", "06":"C", "07":"D", "08":"E", "09":"F", "0a":"G", "0b":"H", "0c":"I", "0d":"J", "0e":"K", "0f":"L", "10":"M", "11":"N", "12":"O", "13":"P", "14":"Q", "15":"R", "16":"S", "17":"T", "18":"U", "19":"V", "1a":"W", "1b":"X", "1c":"Y", "1d":"Z","1e":"!", "1f":"@", "20":"#", "21":"$", "22":"%", "23":"^","24":"&","25":"*","26":"(","27":")","28":"<RET>","29":"<ESC>","2a":"<DEL>", "2b":"\t","2c":"<SPACE>","2d":"_","2e":"+","2f":"{","30":"}","31":"|","32":"<NON>","33":"\"","34":":","35":"<GA>","36":"<","37":">","38":"?","39":"<CAP>","3a":"<F1>","3b":"<F2>", "3c":"<F3>","3d":"<F4>","3e":"<F5>","3f":"<F6>","40":"<F7>","41":"<F8>","42":"<F9>","43":"<F10>","44":"<F11>","45":"<F12>"}

keys = open('key.txt')
output = ""
for line in keys:
    k = line[1]
    n = line[4:6]
    if n == '2a':
        print(output[-1], end='')
    if k == '0':
        output += normalKeys[n]
    elif k == '2':
        output += shiftKeys[n]
  • key: Toggled
  • emoji-aes 解码
    • https://aghorler.github.io/emoji-aes/#
  • 手动解码
    • U2FsdGVkX1+psEGiQ9Bl3PbdKi4mYKSHJfRIoCoRo/bepbG8tJvD+pzC53ApwRR3ekX4K0X6tZ9F2z6PxNVOOw==
import base64
from Crypto.Cipher import AES
import string
emojisInit="🍎🍌🏎🚪👁👣😀🖐ℹ😂🥋✉🚹🌉👌🍍👑👉🎤🚰☂🐍💧✖☀🦓🏹🎈😎🎅🐘🌿🌏🌪☃🍵🍴🚨📮🕹📂🛩⌨🔄🔬🐅🙃🐎🌊🚫❓⏩😁😆💵🤣☺😊😇😡🎃😍✅🔪🗒"
alpha = string.ascii_lowercase+string.ascii_uppercase+string.digits+"+/="
a = "🙃💵🌿🎤🚪🌏🐎🥋🚫😆✅🍍🎤🐘🌏ℹ⌨😍🎈✉🤣🛩🍌🚪🍴ℹ☺🚹❓🍴🔬🌪🍵👣🔄☃👌😎👌🔄👌🔪🍌👁🍍🍌🌏🎃🚰🍵🐍🎅✅🍍🦓😎😊🤣🏹🍍💧🔄🔄🤣👁🥋🚫☺🍴😁🚫😇🚰⏩😍🌿💵🦓😇🛩✖🕹🐎📂📂💧🗒🗒"
base64data = ""
for i in a:
    base64data += alpha[emojisInit.index(i)]
print(base64data)
  • AES解密
    • DASCTF{ad15eecd2978bc5c70597d14985412c4}

好怪啊

题解

  • 下载附件，010打开，发现结尾处存在 kp 怀疑是倒置的zip文件
a = ... # 复制的原 16进制编码
b = []
a = a.split()
for i in range(len(a)):
    b.append(a[len(a) - i - 1])
with open('a.txt', 'w') as w:
    w.write(''.join(b))
  • 导入至010editor，保存为test.zip，解压得到 flag.png
  • 修复文件头，改高，得到flag

奇怪的棋盘

题解

  • 给了一个棋盘，是典型的ADFGVX 密码所用到的棋盘，但是txt中只有11,14,21,22,51,53这六种情况，甚至没有6的出现，所以应该不是直接对应ADFGVX密码，而是对应了波利比奥斯方阵

a b c d e
f g h i/j k
l m n o p
q r s t u
v w x y z

  • 写脚本转化
b = "11,22,11,53,53,14,11,22,22,51,22,22,51,14,51,11,14,11,51,53,14,22,11,14,51,22,14,51,11,11,14,14,14,14,21,53,11,21,11,21,14,22,14,51,53,53,14,22,22,14,22,22,14,53,14,14,21,14,14,53,51,22,53,11,14,22,51,14,21,53,51,51,11,11,14,14,53,14,53,53,11,14,14,51,22,22,22,53,22,53,53,53,53,22,53,53,22,22,53,22,14,51,51,51,22,22,22,11,22,11,11,11,11,22,11,11,22,22,11,22,14,14,14,11,22,11,22,22,22,11,22,22,11,22,11,22,11,11,11,51,11,11,11,53,22,53,22,22,22,53,22,22,53,22,53,22,53,53,53,51"
s = b.split(',')
print(s)
ans = ""
bns = ""
print(int(s[0][1]))
for i in range(len(s)):
    if s[i] == '11':
        ans = ans + 'A'
    if s[i] == '14':
        ans = ans + 'D'
    if s[i] == '22':
        ans = ans + 'G'
    if s[i] == '21':
        ans = ans + 'F'
    if s[i] == '51':
        ans = ans + 'V'
    if s[i] == '53':
        ans = ans + 'X'
print(ans)
  • 图片LSB隐写，得到base32的keyword
    • LastKey{Yusayyds}
  • 得到ADFGVX密码的密文，解密
    • DASCTF{d859c41c530afc1c1ad94abd92f4baf8}

key square:ph0qg64mea1yl2nofdxkr3cvs5zw7bj9uti8
key words:Yusayyds
密文：AGAXXDAGGVGGVDVADAVXDGADVGDVAADDDDFXAFAFDGDVXXDGGDGGDXDDFDDXVGXADGVDFXVVAADDXDXXADDVGGGXGXXXXGXXGGXGDVVVGGGAGAAAAGAAGGAGDDDAGAGGGAGGAGAGAAAVAAAXGXGGGXGGXGXGXXXV
解密：4441534354467b64383539633431633533306166633163316164393461626439326634626166387d

MISCShengsaiWEB
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Source: github.com/k4yt3x/flowerhd
	

	

		
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花!
	


									

			

			
			
		

	






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